Staad pro打印构件内力和支座反力的命令前面显示问号是怎么回事啊
zly_397758902
2014年08月28日 23:54:54
只看楼主

有没有大神帮帮忙啊,是不是因为破解不成功的原因啊。

有没有大神帮帮忙啊,是不是因为破解不成功的原因啊。
zly_397758902
2014年08月28日 23:56:00
2楼
1. STAAD PLANE
INPUT FILE: Example 1.STD
2. START JOB INFORMATION
3. ENGINEER DATE 28-AUG-14
4. END JOB INFORMATION
5. INPUT WIDTH 79
6. UNIT FEET KIP
7. JOINT COORDINATES
8. 1 0 0 0; 2 30 0 0; 3 0 20 0; 4 10 20 0; 5 20 20 0; 6 30 20 0; 7 0 35 0
9. 8 30 35 0; 9 7.5 35 0; 10 22.5 35 0; 11 15 35 0; 12 5 38 0; 13 25 38 0
10. 14 10 41 0; 15 20 41 0; 16 15 44 0
11. MEMBER INCIDENCES
12. 1 1 3; 2 3 7; 3 2 6; 4 6 8; 5 3 4; 6 4 5; 7 5 6; 8 7 12; 9 12 14; 10 14 16
13. 11 15 16; 12 13 15; 13 8 13; 14 9 12; 15 9 14; 16 11 14; 17 11 15; 18 10 15
14. 19 10 13; 20 7 9; 21 9 11; 22 10 11; 23 8 10
15. DEFINE PMEMBER
16. 1 PMEMBER 1
17. DEFINE MATERIAL START
18. ISOTROPIC STEEL
19. E 4.28151E+006
20. POISSON 0.3
21. DENSITY 0.489024
22. ALPHA 1.2E-005
23. DAMP 0.03
24. END DEFINE MATERIAL
25. MEMBER PROPERTY AMERICAN
26. 1 3 4 TABLE ST W14X90
27. 2 TABLE ST W10X49
28. 5 TO 7 TABLE ST W21X50
29. 8 TO 13 TABLE ST W18X35
30. 14 TO 23 TABLE ST L40404
31. CONSTANTS
32. BETA 0 MEMB 2 5 16
33. BETA 90 MEMB 3 4
34. MATERIAL STEEL ALL
35. MEMBER TRUSS
36. 14 TO 23
37. MEMBER RELEASE
38. 5 START MZ
39. UNIT INCHES KIP
40. SUPPORTS
STAAD PLANE -- PAGE NO. 2

41. 1 FIXED
42. 2 PINNED
43. UNIT FEET KIP
44. LOAD 1 LOADTYPE DEAD TITLE DLL
45. JOINT LOAD
46. 4 5 FY -15
47. 11 FY -35
48. MEMBER LOAD
49. 8 TO 13 UNI Y -0.9
50. 6 UNI GY -1.2
51. LOAD 2 LOADTYPE WIND TITLE WL
52. MEMBER LOAD
53. 1 2 UNI GX 0.6
54. 8 TO 10 UNI Y -1.
55. LOAD COMB 3 COMBINATION LOAD CASE 3
56. 1 0.75 2 0.75
57. PERFORM ANALYSIS



P R O B L E M S T A T I S T I C S
-----------------------------------

NUMBER OF JOINTS/MEMBER+ELEMENTS/SUPPORTS = 16/ 23/ 2

SOLVER USED IS THE OUT-OF-CORE BASIC SOLVER

ORIGINAL/FINAL BAND-WIDTH= 5/ 4/ 15 DOF
TOTAL PRIMARY LOAD CASES = 2, TOTAL DEGREES OF FREEDOM = 43
SIZE OF STIFFNESS MATRIX = 1 DOUBLE KILO-WORDS
REQRD/AVAIL. DISK SPACE = 12.0/ 219452.7 MB


ZERO STIFFNESS IN DIRECTION 6 AT JOINT 9 EQN.NO. 21
LOADS APPLIED OR DISTRIBUTED HERE FROM ELEMENTS WILL BE IGNORED.
THIS MAY BE DUE TO ALL MEMBERS AT THIS JOINT BEING RELEASED OR
EFFECTIVELY RELEASED IN THIS DIRECTION.
ZERO STIFFNESS IN DIRECTION 6 AT JOINT 11 EQN.NO. 31
ZERO STIFFNESS IN DIRECTION 6 AT JOINT 10 EQN.NO. 37


58. LOAD LIST 1 3
59. FINISH
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zjjhxyzt
2014年09月08日 17:44:41
3楼
我也出现这个问题,最后计算结果位零
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