1.9.2 配筋计算 MⅠmax = 14.8kN·m MⅡmax = 66.4kN·m ①号筋 AsⅠ = 124mm (x = 4mm) 相对受压区高度 ξ = 0.009 as = 52mm 配筋率 ρ = 0.01% ρmin = 0.15% AsⅠmin = 1701mm (As = 1806) ②号筋 AsⅡ = 554mm (x = 21mm) 相对受压区高度 ξ = 0.052
MⅠmax = 14.8kN·m MⅡmax = 66.4kN·m
①号筋 AsⅠ = 124mm (x = 4mm) 相对受压区高度 ξ = 0.009
as = 52mm 配筋率 ρ = 0.01%
ρmin = 0.15% AsⅠmin = 1701mm (As = 1806)
②号筋 AsⅡ = 554mm (x = 21mm) 相对受压区高度 ξ = 0.052
as = 40mm 配筋率 ρ = 0.10%
ρmin = 0.15% AsⅡmin = 930mm 12Φ10@125 (As = 942)
X 轴方向截面面积 Acb = h1 * b + (b + hc + 2*0.05) * (H - h1) / 2 = 0.62m
Y 轴方向截面面积 Acl = h1 * l + (l + bc + 2*0.05) * (H - h1) / 2 = 1.13m
他的配筋 按最小配筋率来算的,但面积选定是上面的面积?对不对呢?是不是太大了呢?还有就是配筋的时候他用23Φ10@125 ?我不能根据AsⅠmin = 1701mm这个来直接选择Φ16@110 吗?这个不是正好可以大于1701的,为什么选择Φ10@125,这个才628.还有就是他的钢筋1跟2 有没有弄反呢?