大家帮我看看,为什么PMCAD计算板的配筋时,实际配的钢筋面积要比计算值小?我出施工图时是否要认为地将配筋加大到比计算值大呢?以下计算书的内容计算结果: Mx =(0.01059+0.03304/5)*(1.20* 10.5+1.40* 15.0)* 5.3^2 = 16.24kN·M 考虑活载不利布置跨中X向应增加的弯矩: Mxa =(0.02862+0.07093/5)*(1.4* 15.0)* 5.3^2 = 25.25kN·M
计算结果:
Mx =(0.01059+0.03304/5)*(1.20* 10.5+1.40* 15.0)* 5.3^2 = 16.24kN·M
考虑活载不利布置跨中X向应增加的弯矩:
Mxa =(0.02862+0.07093/5)*(1.4* 15.0)* 5.3^2 = 25.25kN·M
Mx= 16.24 + 25.25 = 41.49kN·M
Asx=1013.26mm2,实配φ12@150 (As = 754.mm2)
ρmin = 0.215% , ρ = 0.251%
My =(0.03304+0.01059/5)*(1.20* 10.5+1.40* 15.0)* 5.3^2= 33.19kN·M
考虑活载不利布置跨中Y向应增加的弯矩:
Mya =(0.07093+0.02862/5)*(1.4* 15.0)* 5.3^2 = 45.22kN·M
My= 33.19 + 45.22 = 78.40kN·M
Asy=1521.80mm2,实配φ16@180 (As =1117.mm2)
ρmin = 0.215% , ρ = 0.372%
Mx' =0.05698*(1.20* 10.5+1.40* 30.0)* 5.3^2 = 87.39kN·M
Asx'=1548.98mm2,实配φ14@125 (As =1232.mm2,可能与邻跨有关系)
ρmin = 0.215% , ρ = 0.411%
My' =0.07472*(1.20* 10.5+1.40* 30.0)* 5.3^2 = 114.59kN·M
Asy'=2059.91mm2,实配φ16@125 (As =1608.mm2,可能与邻跨有关系)
ρmin = 0.215% , ρ = 0.536%